Return line of largest field in list of dictionaries text file with Python?

I'm writing a Python script. I need to return line that contain largest 'uid' field from a text file. For example, in the below text file example:

{
    "uid": 683,
    "user_id": "2",
    "timestamp": datetime.datetime(2020, 5, 17, 16, 39, 54),
    "status": 1,
    "punch": 0,
}, {
    "uid": 684,
    "user_id": "4",
    "timestamp": datetime.datetime(2020, 5, 17, 16, 41, 20),
    "status": 1,
    "punch": 0,
}

Return Text File ex:

{
    "uid": 684,
    "user_id": "4",
    "timestamp": datetime.datetime(2020, 5, 17, 16, 41, 20),
    "status": 1,
    "punch": 0,
}

Here is my solution, instead of reading a text file I used a text from string variable text.

Final result (entry with maximal uid) is contained inside max_entry variable. This result I write as string into text file result.txt.

Try it online!

import datetime

text = """
{
    "uid": 683,
    "user_id": "2",
    "timestamp": datetime.datetime(2020, 5, 17, 16, 39, 54),
    "status": 1,
    "punch": 0,
}, {
    "uid": 684,
    "user_id": "4",
    "timestamp": datetime.datetime(2020, 5, 17, 16, 41, 20),
    "status": 1,
    "punch": 0,
}
"""

data = eval('[' + text + ']')
max_entry = max(data, key = lambda e: e['uid'])
print(max_entry)

with open('result.txt', 'w', encoding = 'utf-8') as f:
    f.write(str(max_entry))

Output:

{'uid': 684, 'user_id': '4', 'timestamp': datetime.datetime(2020, 5, 17, 16, 41, 20), 'status': 1, 'punch': 0}