How to get a link with web scraping

I would like to create a web scraping with some Python library (Beautiful Soup, for example) to collect the YouTube links on this page:

https://www.last.fm/tag/rock/tracks

Basically, I want to download the title of the song, the name of the artist and the link to Youtube. Can anyone help me with some code?

In the future, provide some code to show what you have attempted.

I have expanded on Fabix answer. The following code gets the Youtube link, song name, and artist for all 20 pages on the source website.

from bs4 import BeautifulSoup
import requests

master_url = 'https://www.last.fm/tag/rock/tracks?page={}'

headers = {
"User-Agent": "Mozilla/5.0 (iPhone; CPU iPhone OS 5_1 like Mac OS X) AppleWebKit/534.46 (KHTML, like Gecko) Version/5.1 Mobile/9B179 Safari/7534.48.3"
}

for i in range(1,20):
    response = requests.get(master_url.format(i), headers=headers)
    soup = BeautifulSoup(response.content, 'html.parser')

    chart_items = soup.find_all(class_='chartlist-row')

    for chart_item in chart_items:
        youtube_link = chart_item.find('a')['href']
        artist = chart_item.find('td', {'class':'chartlist-artist'}).find('a').text
        song_name = chart_item.find('td', {'class': 'chartlist-name'}).find('a').text
        print('{}, {}, {}'.format(song_name, artist, youtube_link))