If the string has an alphabet or a number, return true. Otherwise, return false.
I have to do this, right?
return re.match('[A-Z0-9]',thestring)
Use thestring.isalnum()
method.
>>> '123abc'.isalnum()
True
>>> '123'.isalnum()
True
>>> 'abc'.isalnum()
True
>>> '123#$%abc'.isalnum()
>>> a = '123abc'
>>> (a.isalnum()) and (not a.isalpha()) and (not a.isnumeric())
True
>>>