I tried writing a code which have a function with if else loop. I wanted a counter of the number of times that if statement is ran

Please help me. I wanted the counter num variable to add everytime the function is ran. But its not working, please tell me why I did wrong. If I use return num then the code is ending which I dont want, but n =+1 is not working, please help. Thanks a lot.

def prompt():
num = 1
print(num)
question = input("Do you want to add a file(y,n): ")

if question == "y":


    file = input("Which File?: ")
    nukefile.append(file)
    st_frm = input("Start frame: ")
    start_frame.append(st_frm)
    en_frm = input("End Frame: ")
    end_frame.append(en_frm)

    #return num + 1

    num =+1 
    print(num)

    nukew = str("start /wait Nuke11.1.exe -x -"+st_frm+"-"+en_frm+" "+file)
    nukewrite.append(nukew)
    que = (str(num)+". "+file+"--"+st_frm+","+en_frm)
    for_artist.append(que)


    for x in for_artist:
        print(x)

    prompt()
    return num


elif question == "n":
    print(nukewrite)
    f = open(batchfile, "a")
    for shotsa in nukewrite:
        f.write('\n'+shotsa+'\n')
    print("Following files will render:")
    for shotsb in nukefile:
        print(shotsb)
    
    f.close()
else:
    print("Invalid entry")
    prompt()

If you want to count how many times the function runs and keep it recursive, you'll need to define prompt.num outside of prompt. You can define it under the function or use a decorator and define it above.

def prompt():
    prompt.num += 1
    your code

prompt.num = 0