I'm having a logic error in my Tic Tac Toe game I have written the code using Java This is the method that will place O every time I place an X
/* creating method to place O*/
private void placeO(){
String[] arr = { b1.getText() , b2.getText() , b3.getText(),
b4.getText() , b5.getText() , b6.getText(),
b7.getText() , b8.getText() , b9.getText()};
boolean check = true;
try{
boolean result = checkForWinner(arr);
while(check){
/*if there is a winner or tie then stop */
if(result == true){
break;
}
int r = (int)( Math.random()* 8 ) ;
/*generate random number between 0 and 8 */
if(arr[r] == ""){
switch(r){
case 0 : b1.setText("O");break;
case 1 : b2.setText("O");break;
case 2 : b3.setText("O");break;
case 3 : b4.setText("O");break;
case 4 : b5.setText("O");break;
case 5 : b6.setText("O");break;
case 6 : b7.setText("O");break;
case 7 : b8.setText("O");break;
case 8 : b9.setText("O");
}
check = false;
}
}
}catch(Error e){
System.out.print(e);
}
}
each time i press the button this event will happend
private void b8ActionPerformed(java.awt.event.ActionEvent evt) {
if(b8.getText() == ""){
b8.setText("X");
placeO();
}
}
the problem i'm facing that each time O wins the message doesn't appear until I place another X is there a way to fix this error logic ?
Try checking for the winner in your private void b8ActionPerformed
after you placed your "X" and put the boolean result = checkForWinner(arr);
at the end of "O"s turn.
This should fix the logic error.