[SOLVED] How do I find files with a greater numerical value than a file based upon timestamp in the filename

How do I find files with a greater numerical value than a file based upon timestamp in the filename

New to Linux and bash shell scripting so any assistance would be greatly appreciated.

Edit:

I'm looking to find all files in a directory with a greater numerical filename than another filename uising a bash shell script.

The filename being used for comparison: Jimmy_1_2019-05-11-070001.csv

My Files :

 Jimmy_1_2019-05-11-094501.csv
 Jimmy_1_2019-05-11-093001.csv
 Jimmy_1_2019-05-11-091501.csv 
 Jimmy_1_2019-05-11-090001.csv 
 Jimmy_1_2019-05-11-070001.csv

I want my output to look like this:

 Jimmy_1_2019-05-11-094501.csv
 Jimmy_1_2019-05-11-093001.csv
 Jimmy_1_2019-05-11-091501.csv
 Jimmy_1_2019-05-11-090001.csv

Solution

X='Jimmy_1_2019-05-11-070001.csv'
for n in `ls`; do   # run this in the folder with your files
  if [[ $n > $X ]]; then
    echo $n;
  fi;
done

Example:

> ls
Jimmy_1_2019-05-11-070001.csv  Jimmy_1_2019-05-11-091501.csv  Jimmy_1_2019-05-11-094501.csv
Jimmy_1_2019-05-11-090001.csv  Jimmy_1_2019-05-11-093001.csv

> ./../so1.sh 
Jimmy_1_2019-05-11-090001.csv
Jimmy_1_2019-05-11-091501.csv
Jimmy_1_2019-05-11-093001.csv
Jimmy_1_2019-05-11-094501.csv