[SOLVED] SQWRL Query to Select Difference of Grouped Sets

SQWRL Query to Select Difference of Grouped Sets

Let's say that I have this information

Individual  |   Sex     |   HairColor
---------------------------------------
Joseph      |   Male    |   Black
Peter       |   Male    |   Black
Kevin       |   Male    |   Blonde
Andrew      |   Male    |   Brown
Boris       |   Male    |   Brown
Chistine    |   Female  |   Black
Julia       |   Female  |   Black
Julieth     |   Female  |   Brown
Judith      |   Female  |   Brown
Mary        |   Female  |   Blonde

My individuals are all different. I have the class Male and Female asserted to each one. And I also have the property hasHairColor asserted to everyone with its value.

The question is, how can I query all the males with hair color different from black (the ontology may have many other hair colors)?

So far, I have tryied this queries with faulty results...

1. Male(?x) ^ Male(?y) ^ hasHairColor(?y, "Black") ^ differentFrom(?x, ?y) -> sqwrl:select(?x)
2. Male(?x) ^ Male(?y) ^ hasHairColor(?y, "Black")  .  sqwrl:makeSet(?males, ?x) ^ sqwrl:groupBy(?males, ?x) ^ sqwrl:makeSet(?blacks, ?y) ^ sqwrl:groupBy(?blacks, ?y)  .  sqwrl:notEqual(?males, ?blacks) -> sqwrl:select(?x)
3. Male(?x) ^ Male(?y) ^ hasHairColor(?y, "Black")  .  sqwrl:makeSet(?males, ?x) ^ sqwrl:groupBy(?males, ?x) ^ sqwrl:makeSet(?blacks, ?y) ^ sqwrl:groupBy(?blacks, ?y)  .  sqwrl:difference(?diff, ?males, ?blacks) -> sqwrl:select(?x)

I'm missing something in the way the joins are made. The result works but only when one of the sets has only one element (i.e. if I try to remove blondes)

I'm using Protege 5.2 with the SWRL and SQWRL Tab 2.0.5

Thanks in advance

Solution

The issue is still pending, but the solution was to use SPARQL to achieve what I wanted.

If you need more information about the open issue. You can find it here https://github.com/protegeproject/swrlapi/issues/43