Need to write the following SQL Query in Sequelize Node js
select a, b, c
from (
select tbl.*,
count(*) over(partition by a) cnt,
row_number() over (partition by a order by b) brn,
row_number() over (partition by a order by c) crn
from tbl
where c in (4, 5)
) t
where cnt = 2 and brn = crn;
This is what I've come up with. I cannot figure out where to put the condition where cnt = 2 and brn = crn;
t.findAll({
attributes: {
include: [
[sequelize.literal('count(*) over(partition by a)'),'cnt'],
[sequelize.literal('row_number() over (partition by a order by b)'),'brn'],
[sequelize.literal('row_number() over (partition by a order by c)'),'crn'],
]
},
where: {
c: {[Op.in]:[4,5]},
}
})
Sequelize doesn't seem to support selecting from subqueries (https://github.com/sequelize/sequelize/issues/5354)
You can use a raw query instead (https://sequelize.org/master/manual/raw-queries.html):
const { QueryTypes } = require('sequelize');
let result = await sequelize.query(`
select a, b, c
from (
select tbl.*,
count(*) over(partition by a) cnt,
row_number() over (partition by a order by b) brn,
row_number() over (partition by a order by c) crn
from tbl
where c in (4, 5)
) t
where cnt = 2 and brn = crn;
`, {type: QueryTypes.SELECT});