How to multiply with add and shift algorithm in 6502 when the multiplicand is in the accumulator?

So I'm trying to multiply by using add and shift. I want to store the multiplicand in the accumulator and the multiplicand in the X-register. I genuinely don't know why my code isn't working but I suspect its because of the multiplicand being in the accumulator and putting the product in a separate register.

Here is my code so far:

      LDA #49
      LDX #8
      LDY #$8
      STA $700
      STX $704
loop:           ; if 1
      BCC  loop2    ; if 0, go to loop2
      CLC       ; clear carry for adc
      ADC $700      ; adc
loop2: ;     if 0
      ROL $700      ; left shift
      CLC
      ROR $704
      DEY
      BNE loop      ; if not 0, go to loop
      STA $700      ; store A in product register

Thank you for your help

This is the corrected version. Check double semicolon for the changes. Biggest mistake was to forget resetting accumulator and carry flag before the first loop.

      LDA #49
      LDX #8
      LDY #9    ;; you need to increase your loop by 1
      STA $700
      STX $704
      LDA #$00  ;; you need to reset acc
      CLC       ;; and clear carry
loop:           ; if 1
      BCC  loop2    ; if 0, go to loop2
      CLC       ; clear carry for adc
      ADC $700      ; adc
loop2: ;     if 0

      ;ROL $700     ;; these three lines
      ;CLC          ;; are replaced with
      ;ROR $704     ;; the two lines below

      ROR        ;; this is
      ROR $704   ;; faster

      DEY
      BNE loop      ; if not 0, go to loop
      STA $700      ; store A in product register