I am getting started with Julia, and am watching this video, and at the time I linked to, the presenter runs the command
palette = distinguishable_colors(100)
Now if I run that in my terminal (xfce4-terminal), I just get output that looks
RGB{N0f8}(0.471,0.482,0.231)
RGB{N0f8}(0.714,0.976,0.851)
RGB{N0f8}(0.855,0.0,0.247)
RGB{N0f8}(0.18,0.129,0.141)
RGB{N0f8}(0.0,0.345,0.082)
RGB{N0f8}(1.0,0.557,0.114)
RGB{N0f8}(0.4,0.455,0.694)
RGB{N0f8}(0.0,0.804,0.678)
RGB{N0f8}(0.0,0.498,0.388)
RGB{N0f8}(0.6,0.435,0.239)
Is there a way to get it to output actually colors on the terminal (like in the video)? Is this something that has to be updated in a separate config (and what exactly?), or something that needs to be tuned in Julia?
Sure you can just use the Crayons package.
This package is using Int
s for representation of colors and the API of Colors.jl
is rather verbose here (unless you want directly access pallette
object fields which would be not elegant).
using Color, Crayons
palette = distinguishable_colors(8);
crs = [Crayon(foreground = reinterpret.((red(palette[i]), green(palette[i]),blue(palette[i]))) ) for i in 1:8];
println.(crs, string.("This is line ",1:8));
Note that the first line ha black color so it is not visible, however you can always add something like background=:white
to the Crayon
constructor.