So, I have two tables:
EMP {EMP_NO, EMP_SALARY, EMP_DEPT_NO}
DEPT {DEPT_NO, DEPT_MNG}
EMP_NO, DEPT_NO - primary keys, EMP_DEPT_NO - external key to DEPT, DEPT_MNG - external key to EMP.
I need to find all departments where every employee has the same salary.
You can use the COUNT DISTINCT
in the HAVING
section to achieve that. the COUNT DISTINCT
will return how many variations of salary there are in a certain dept.
SELECT DEPT_NO
FROM DEPT JOIN EMP ON DEPT.DEPT_NO=EMP.EMP_DEPT_NO
GROUP BY DEPT_NO
HAVING COUNT(DISTINCT SALARY) =1