given that
int w = 1;
int x = 6;
int y = 5;
int z = 0;
z = !z || !x && !y;
printf("%d\n", z);
z = x-- == y + 1;
printf("%d\n", z);
Could someone explain how the line below would evaluate to 1 if x-- is 5 and y+1 is 6?
z = x-- == y + 1;
The expression x--
evaluated to the value of x
before being decremented.
So x-- == y + 1
is the same as 6 == 5 + 1
which is true, then the value 1 is assigned to z
.