As a (former) Ubuntu user, I was used to executing commands like
nautilus path/to/folder
or
pcmanfm path/to/folder
depending on the file-explorer app installed on my system.
This led to the result that the file-explorer was opened up in the directory of interest, which I called here for exemplary reasons path/to/folder
.
Up until now, I could not figure out how to do the same on Windows 10
using the git bash
(MINGW64) - shell.
Thanks to the comment of @ssbssa,
I found 3 versions that worked for me using /c/Users/username/Downloads/Test_files
as test-path:
$ explorer `cygpath -w "C:\Users\username\Downloads\Test_files"`
$ explorer `cygpath -w "/c/Users/username/Downloads/Test_files"`
$ explorer `cygpath -w /c/Users/username/Downloads/Test_files`
It is important to note that by employing quotes ".."
the command will be accepted no matter
which directory-separation type is implemented ("/"
or "\"
depending on your OS).
When leaving the quotes out, it'll work only with the linux-style "/"
.
What's more, it is essential to wrap the cygpath -w path/to/folder
- command into
a pair of back-ticks "", otherwise the entire command will open a default folder in your windows explorer instead of the target folder.
This is by the way (one of) the default fall-back behavior in case something goes wrong, as far as I've experienced it.
To be honest, I would love to know a way of doing the same thing just with a command like
$ explorer /c/Users/username/Downloads/Test_files
since otherwise it seems a bit unpractical to type this cygpath -w ..
- wrapper around the command.
If you know a simplification of that, or an easier approach altogether, kindly let me know.
EDIT - Solution found thanks to @ssbssa's comment:
One can set a new bash
-function in the bash shell
via
explore() { explorer `cygpath -w $1`; }
Then, open the Windows Explorer
in the folder of interest via
explore path/to/folder