C error expected ‘char **’ but argument is of type ‘char (*)[10]’

I am trying to implement my version of strcat. However, I get below warning and my code crashes while running. I am passing &p from main to make permanent changes to variable p in the main function.

Warning:

note: expected ‘char **’ but argument is of type ‘char (*)[10]’

Code:

#include <string.h>
#include <stdio.h>

void mystrcat(char **p, char *q)
{
    while (**p != '\0')
    {
        *p++;
    }

    while (*q != '\0')
    {
        **p = *q;
        (*p)++;
        q++;
    }
    *p = '\0';
}

int main()
{
    char p[10] = "ravi";
    char q[12] = "ra";

    mystrcat(&p, q);
    printf("%s", p);
}

Instead of a pointer to a pointer to char, just pass a pointer to char, it will also make the modification permanent. That's pretty much how the string.h strcat works. Maybe also check for NULL pointers.

#include <stdio.h>
#include <stdlib.h>

char *mystrcat(char *p, char *q)
{
    char *ptr = p; /* so you dont alter p's initial address */

    if (p == NULL || q == NULL)
    {
        exit(EXIT_FAILURE);
    }

    while(*ptr != '\0')
    {
        ptr++;
    }

    while(*q != '\0')
    {
        *ptr = *q;
        ptr++; /* you dont have to dereference */
        q++;
    }
    *ptr = '\0';

    return p;
}

int main(void)
{
    char p[100]="hello";
    char q[12]="world";

    mystrcat(p, q);
    printf("%s", p);

    return 0;
}