I am trying to use valarray since it is much like MATLAB while operating vector and matrices. I first did some performance check and found that valarray cannot achieve the performance declared as in the book C++ programming language by Stroustrup.
The test program actually did 5 million multiplication of doubles. I thought that c = a*b would at least be comparable to the for
loop double type element multiplication, but I am totally wrong. I tried on several computers and Microsoft Visual C++ 6.0 and Visual Studio 2008.
By the way, I tested on MATLAB using the following code:
len = 5*1024*1024;
a = rand(len, 1);
b = rand(len, 1);
c = zeros(len, 1);
tic;
c = a.*b;
toc;
And the result is 46 ms. This time is not high precision; it only works as a reference.
The code is:
#include <iostream>
#include <valarray>
#include <iostream>
#include "windows.h"
using namespace std;
SYSTEMTIME stime;
LARGE_INTEGER sys_freq;
double gettime_hp();
int main()
{
enum { N = 5*1024*1024 };
valarray<double> a(N), b(N), c(N);
QueryPerformanceFrequency(&sys_freq);
int i, j;
for (j=0 ; j<8 ; ++j)
{
for (i=0 ; i<N ; ++i)
{
a[i] = rand();
b[i] = rand();
}
double* a1 = &a[0], *b1 = &b[0], *c1 = &c[0];
double dtime = gettime_hp();
for (i=0 ; i<N ; ++i)
c1[i] = a1[i] * b1[i];
dtime = gettime_hp()-dtime;
cout << "double operator* " << dtime << " ms\n";
dtime = gettime_hp();
c = a*b ;
dtime = gettime_hp() - dtime;
cout << "valarray operator* " << dtime << " ms\n";
dtime = gettime_hp();
for (i=0 ; i<N ; ++i)
c[i] = a[i] * b[i];
dtime = gettime_hp() - dtime;
cout << "valarray[i] operator* " << dtime<< " ms\n";
cout << "------------------------------------------------------\n";
}
}
double gettime_hp()
{
LARGE_INTEGER tick;
extern LARGE_INTEGER sys_freq;
QueryPerformanceCounter(&tick);
return (double)tick.QuadPart * 1000.0 / sys_freq.QuadPart;
}
The running results: (release mode with maximal speed optimization)
double operator* 52.3019 ms
valarray operator* 128.338 ms
valarray[i] operator* 43.1801 ms
------------------------------------------------------
double operator* 43.4036 ms
valarray operator* 145.533 ms
valarray[i] operator* 44.9121 ms
------------------------------------------------------
double operator* 43.2619 ms
valarray operator* 158.681 ms
valarray[i] operator* 43.4871 ms
------------------------------------------------------
double operator* 42.7317 ms
valarray operator* 173.164 ms
valarray[i] operator* 80.1004 ms
------------------------------------------------------
double operator* 43.2236 ms
valarray operator* 158.004 ms
valarray[i] operator* 44.3813 ms
------------------------------------------------------
Debugging mode with same optimization:
double operator* 41.8123 ms
valarray operator* 201.484 ms
valarray[i] operator* 41.5452 ms
------------------------------------------------------
double operator* 40.2238 ms
valarray operator* 215.351 ms
valarray[i] operator* 40.2076 ms
------------------------------------------------------
double operator* 40.5859 ms
valarray operator* 232.007 ms
valarray[i] operator* 40.8803 ms
------------------------------------------------------
double operator* 40.9734 ms
valarray operator* 234.325 ms
valarray[i] operator* 40.9711 ms
------------------------------------------------------
double operator* 41.1977 ms
valarray operator* 234.409 ms
valarray[i] operator* 41.1429 ms
------------------------------------------------------
double operator* 39.7754 ms
valarray operator* 234.26 ms
valarray[i] operator* 39.6338 ms
------------------------------------------------------
I suspect that the reason c = a*b
is so much slower than performing the operations an element at a time is that the
template<class T> valarray<T> operator*
(const valarray<T>&, const valarray<T>&);
operator must allocate memory to put the result into, then returns that by value.
Even if a "swaptimization" is used to perform the copy, that function still has the overhead of
valarray
valarray
(it's possible that this might be optimized away)valarray
valarray
as it is initialized or set with result valuesvalarray
that gets replaced by the result