By using x *A as a receiver I could reference B as x.B
But I'd like to keep methods related to the B nested struct in their own namespace (if you will) by having a different receiver than the methods of the parent struct. (And avoiding func name clashes)
type A struct {
//...
B struct {
// ...
}
}
//...
func (x *A.B) method() {
}
Error: A.B undefined (type A has no method B) compiler(MissingFieldOrMethod)
I just figured out I have to define B's type outside struct A and reference B directly in the receiver.
In my first example, B is an attribute of A of an unnamed type, and of course for a receiver parameter you have to reference a named type.
(Or is there a way to reference an unnamed struct from its instance?)
Corrected code:
type A struct {
//...
b B
}
type B struct {
}
}
//...
func (x *B) method() {
}
//...
a A = &A{}
a.b.method()