I know this should be simple command but I am not able to figure out the mistake. I think it something with the syntax
So I have a file name script.sh
which is stored in a variable var1
. So flow goes like this
#! /bin/bash
echo "Enter commit hash"
read commit
var1=`git diff-tree --no-commit-id --name-only -r "$commit"`
echo $var1
locate -br "$var1"
The code works fine till echo $var1
, but I am not able to find/locate the path where file exisits.
Expected output
script.sh
/c/training
Assuming script.sh is present in /c/training.
Just in case, make sure to use name-only
not name-oly
That would explain why var1
is empty.
Also, use the suggestions from shellcheck for your bash script.
#! /bin/bash
echo "Enter commit hash"
read -r commit
var1=$(git diff-tree --no-commit-id --name-only -r "$commit")
echo "$var1"
locate -br "$var1"