React Native - get url search params

I am trying to get URL params in a React Native app.

What I tried to do:

1. fails because searchParams is an empty list

const parsedUrl = new URL(url)

// here the searchParams are empty list
console.log(parsedUrl.searchParams)

2. fails because the following error is shown:

[Error: not implemented]

const parsedUrl = new URLSearchParams(url)
console.log(parsedUrl.get(param))

const getSearchParamFromURL = (url, param) => {
  const include = url.includes(param)

  if (!include) return null

  const params = url.split(/([&,?,=])/)
  const index = params.indexOf(param)
  const value = params[index + 2]
  return value
}

const _url = 'myapp://?code=123123-1123123-418c-33213-123123&param_key=param_value'

getSearchParamFromURL(_url, 'code') // output: 123123-1123123-418c-33213-123123