I have a UserControl that contains two ContentControls that need to have different UserControl Views bound to them at runtime. The attached-Property solution noted here does not seem to work in Silverlight. Or, I am doing something wrong. I also, found this, but it did not bring any joy either.
I had a single ContentControl working by naming it 'ActiveItem'. But, of course, I cannot have two ContentControls with the same name.
Thanks in advance for any help,
Jim
Just expose two public properties on your main view model, each one being an instance of the type of view model you wish to display. Then, in your view have a ContentControl
with the corresponding name. E.g:
public class MyMainViewModel
{
private NavigationViewModel navigation;
private MyContentViewModel main;
public MyMainViewModel()
{
// better to inject factories using constructor injection here
this.Navigation = new NavigationViewModel();
this.Main = new MyContentViewModel();
}
public NavigationViewModel Navigation
{
get { return navigation; }
set { navigation= value; NotifyOfPropertyChanged(() => this.Navigation); }
}
public MyContentViewModel Main
{
get { return main; }
set { main= value; NotifyOfPropertyChanged(() => this.Main); }
}
...
}
<ContentControl x:Name="Navigation" />
...
<ContentControl x:Name="Main" />