Will EXECVP system call supports IO redirections

Will EXECVP system call supports IO redirections

That means is this give desired output

char *args[]={"cat","A.txt","B.txt",">","C.txt",NULL};
execvp(args[0],args);

I mean will the data in A.txt and B.txt goes to C.txt

If no why ?

UPD : I have asked two doubts in comment please clarify it

This is technically not an answer to your question, that has been answered in the comments. But an explanation to how you can do redirection with execvp

When starting a new program with execvp, it will inherit the current file descriptor. So if you setup file descriptor 1 (which is used for stdout) to be redirected to "C.txt" before calling execvp, the new program will write to "C.txt":

// Open "C.txt" for writing, creating it if it doesn't exist, or
// clearing its content if it does exist.
// `mode` should be set as appropriate 
//
int fd = creat("C.txt", mode);
if (fd == -1)
{
   // Swap out error handling to suit your needs
   perror("open failed");
   exit(EXIT_FAILURE);
}

// We want new process to have "C.txt" on file descriptor 1
if (dup2(fd, 1) == -1)
{
   perror("dup failed");
   exit(EXIT_FAILURE);
}


// "C.txt" is now writable on file descriptor 1, so we don't need the
// old one. Actually, the old one could confuse the new executable.
close(fd);


// We can now execute new program. It will inherit current open 
// file descriptors and it will see "C.txt" on file descriptor 1
char *args[]={"cat","A.txt","B.txt",NULL};
execvp(args[0],args);

// If we reach this point, `execvp` failed.
perror("execvp failed");
exit(EXIT_FAILURE);