javascripttypescripteslintdestructuringunused-variables

Remove a property using object destructuring, without eslint no-unused-vars error

Consider the following code where I create a "copy" of x with one of the properties removed, using destructuring:

const x = { a: 1, b: 2, c: 3};
const { a, ...x2} = x;
console.log(x);
console.log(x2);

If I do it like this, @typescript-eslint/no-unused-vars will consider it an error that a is not used.

How can I change the code to fix the error, without explicitly asking eslint to ignore the offending line, preferably still using the destructuring syntax? I.e. I really don't want to use delete, nor do I want to explicitly enumerate all other properties like const x2 = {b: x.b, c: x.c }.

Is there a fancy syntax or weird eslint rule to have my cake and eat it too?

Solution

  • There is a newly added option named ignoreRestSiblings for that rule.

    You could set it to true to ignore your case:

    { "ignoreRestSiblings": true }