svgsvg-transforms

Switch X and Y axis for everything in SVG?

I'm creating a bar chart with SVG, by default bars are vertical. But in some cases it looks better if bars are horizontal, like when there are only 2 bars.

enter image description here

How can I reuse same SVG code and just switch X and Y axis to achieve that? It's actually more than just X and Y and also things like height and width for the rect.

Is that possible? I would like to avoid writing very similar code twice.

Example: I built two charts separately, ideally the second chart should be produced by reusing the code from the first chart.

<style>
  svg { height: 20px; width: 100px;  border: 1px solid #ccc;}
</style>

<svg>
  <rect x="5%" y="60%" width="40%" height="40%" fill="black"/>
  <rect x="55%" y="40%" width="40%" height="60%" fill="black"/>
</svg>

<svg>
  <rect y="5%" x="0%" height="40%" width="40%" fill="black"/>
  <rect y="55%" x="0%" height="40%" width="60%" fill="black"/>
</svg>

Solution

  • Maybe something like this:

    function cloneWithTransformedAttributes(obj1, mapping) {
  // returns copy of obj1 with child node attributes transformed according to mapping.
  const obj2 = obj1.cloneNode(true);
  [...obj1.children].forEach((child, idx)=>{
    Object.keys(mapping).forEach((attribute) => {
      const replacementVal = mapping[attribute].default ?
            mapping[attribute].default :
            child.getAttribute(mapping[attribute]);
        obj2.children[idx].setAttribute(attribute, replacementVal);
    })
  })
  return obj2;
}

mapping = {
x: {
  default: 0
},
y: "x",
width: "height",
height: "width"
}

const verticalSvg = document.getElementsByTagName("svg")[0];
const horizontalSvg = cloneWithTransformedAttributes(verticalSvg, mapping);

const graphs = document.getElementById("graphs");
graphs.appendChild(horizontalSvg);
    <style>
  svg { height: 20px; width: 100px;  border: 1px solid #ccc;}
</style>

<div id="graphs">
  <svg>
    <rect x="5%" y="60%" width="40%" height="40%" fill="black"/>
    <rect x="55%" y="40%" width="40%" height="60%" fill="black"/>
  </svg>
</div>

    Edit: You could also do it with svg transforms but you need to put the inside of the SVG inside a group <g></g>. Here's an example with both a manually calculated transform and a JS solution that calculates the transform by itself by getting the original svg width and height:

    const verticalSvg = document.getElementsByTagName("svg")[0];
const svgStyle = window.getComputedStyle(verticalSvg, null);

const width = parseInt(svgStyle.getPropertyValue("width"));
const height = parseInt(svgStyle.getPropertyValue("height"));
const whRatio = width / height;
const transform = `rotate(90) scale(${1 / whRatio} ${whRatio}) translate(0 -${height})`


const horizontalSvg = verticalSvg.cloneNode(true);
horizontalSvg.children[0].setAttribute("transform", transform);

const graphs = document.getElementById("graphs");
graphs.appendChild(horizontalSvg);
    <style>
  svg { height: 20px; width: 100px;  border: 1px solid #ccc; overflow: visible}
</style>

<div id="graphs">
  <svg>
    <g>
    <rect x="5%" y="60%" width="40%" height="40%" fill="black"/>
    <rect x="55%" y="40%" width="40%" height="60%" fill="black"/>
    </g>
  </svg>
  <svg>
    <!-- Manually calculated and applied transform    -->
    <g transform="rotate(90)
                scale(0.20 5)
                  translate(0 -20)
                  ">
    <rect x="5%" y="60%" width="40%" height="40%" fill="black"/>
    <rect x="55%" y="40%" width="40%" height="60%" fill="black"/>
    </g>
  </svg>
<!-- JS generated SVG will get inserted here   -->
</div>

    In your case, you need to apply the transform to a group holding the SVG contents. If you apply the transform to the SVG itself it will also scale the border according to the scale transform.

    vector-effect="non-scaling-stroke" can not be applied to the border of the SVG which is not part of the SVG itself. But if you are using elements with a "stroke" property inside the SVG then you would probably want to also apply the vector-effect="non-scaling-stroke" attribute to them.