I have a triple nested list and trying to grab the same position of the most inner list elements and join as a list of strings by the second nested level in python.
input=[[['a b c'], ['d e f'], ['g h i']], [['j k l'], ['m n o'], ['p q r']], [['s t u'], ['v w x'], ['y z zz']]]
output=['a b c j k l s t u', 'd e f m n o v w x', 'g h i p q r y z zz']
I found how to flatten the entire lists but in this case, I like to keep the second inner list. Any suggestions appreciated!
Try:
inp = [
[["a b c"], ["d e f"], ["g h i"]],
[["j k l"], ["m n o"], ["p q r"]],
[["s t u"], ["v w x"], ["y z zz"]],
]
out = [" ".join(s for l in t for s in l) for t in zip(*inp)]
print(out)
Prints:
["a b c j k l s t u", "d e f m n o v w x", "g h i p q r y z zz"]