I am currently working on a Java program that takes the arguments of a person's input (I figured that part out) and then adds it to a string to then send it to another person. However, I'm stuck with this one part, where the first argument is not to be included in the message. I originally thought of if (!arg.equals(args[0])){}
, but in the case where the first argument is mentioned again in the message, it also removes that from the message. How do I make it remove the first argument without getting rid of any others exactly like it?
My code right now:
if (args.length<=0){
sender.sendMessage(ChatColor.RED + "No player specified.");
} else {
if (args.length==1){
sender.sendMessage(ChatColor.RED + "No message specified");
} else {
String message = "";
for (String arg : args){
if (!arg.equals(args[0])){
}
}
}
}
You can start the for-loop
from index one. That way the first argument will not be included at all.
if (args.length <= 0) {
sender.sendMessage(ChatColor.RED + "No player specified.");
} else {
if (args.length == 1) {
sender.sendMessage(ChatColor.RED + "No message specified");
} else {
StringBuilder message = new StringBuilder();
for (int i = 1; i < args.length; i++) {
message.append(args[i]);
}
}
}