How to pass context to a different view function?

My models.py:

class fields(models.Model):
      name = models.CharField(max_length=18)
      link = models.TextField()

The link contains the hyperlink of the related name.

My views.py:

def index(request):
    listing = fields.objects.all()
    context ={'listing':'listing'}
    return render(request,'index.html',context)

urls.py

urlpatterns = [
   
    path('admin/', admin.site.urls),
    path('',index,name="index"),
]

template:

 {% for i in listing %}
    <tr>
    <td data-label="name">{{ i.name }}</td>
    <td data-label="Quote"><button><a href ="{{ i.link}} " target="_blank">{{ i.link }}</a></button></td>
    <tr>
 {% endfor %}

This redirects to the hyperlink that is displayed in the template but I want to do some automation after it redirects into this link.

Now, I want to pass the context of this function which only includes the link to the other view function so that another view function will be:

def bypass_link(request):
    # get the link from above function
    # execute some selenium scripts in the link

The simple template to illustrate this will be:

{% for i in listing %}
<tr>
<td data-label="name">{{ i.name }}</td>
<td data-label="Quote"><button><a href ="{ % url 'bypass_link' %} " target="_blank">{{ i.link }}</a></button></td>
<tr>
{% endfor %}

You can pass the id of the object into the url by altering the following:

template

<td data-label="Quote">
    <a href="{% url 'bypass_link' i.id %}" target="_blank">{{ i.link }}</a>
</td>

urls.py

from django.conf.urls import url 

url(r'^bypass_link/(?P<pk>\d+)/$', views.bypass_link, name="bypass_link"),

Then in your function you need to find the same model instance and then extract the link.

def bypass_link(request, pk=None):
    instance = fields.objects.get(pk=pk)
    print(instance.link) # now you have your link

Now you have access to the link via instance.link