Conditional aggregate queries

I've seen other solutions. Curious if this method of solving these would work.

TABLES:

attendance_events : date | student_id | attendance

all_students : student_id | school_id | grade_level | date_of_birth | hometown

What percent of students attend school on their birthday?

With agg_join as (SELECT att.date as dates, att.attendance as attendance, als.date_of_birth as DOB, att.student_id as student_id
      FROM attendance_events att
      join all_students als on att.student_id = als.studentid)
      
Select count(DISTINCT student_id) as total_students, 
  count( Distinct case when DOB = dates and attendance = TRUE) as count_of_DOBS,
  total_students/ count_of_DOBS as percent_of_student
from agg_join

Which grade level had the largest drop in attendance between yesterday and today?

With agg_join as ( SELECT att.date as dates, att.attendance as attendance, als.grade_level as grade
      FROM attendance_events att
      join all_students als on att.student_id = als.studentid)
      
Select grade,  
      case when dates ( 'd', -1, currentdate) and attendance = True then 1
      else 0 end as yesterday_att,

       case when dates ( 'd', currentdate) and attendance = True then 1
      else 0 end as Today_att, 
      
      (Today_att - yesterday_att) * -1 AS DIFF
      
from agg_join
Group by grade
Order by DIFF DESC
Limit 1

What percent of students attend school on their birthday?

SELECT 100.0
     * count(*) FILTER (WHERE EXISTS (SELECT FROM attendance_events a
                                      WHERE a.student_id = s.student_id
                                      AND f_mmdd(a.date) = f_mmdd(s.date_of_birth)
                                     ))
     / count(*) AS percentage
FROM   all_students s;

Where the custom function f_mmdd() is defined here:

• How do you do date math that ignores the year?

See:

• Convert numeric result to percentage with decimal digits

About the aggregate FILTER clause:

• Aggregate columns with additional (distinct) filters

Which grade level had the largest drop in attendance between yesterday and today?

SELECT s.grade_level
     , count(*) FILTER (WHERE a.date = CURRENT_DATE - 1) AS yesterday_attendance
     , count(*) FILTER (WHERE a.date = CURRENT_DATE) AS today_attendance
FROM   attendance_events a
JOIN   all_students s USING (student_id)
WHERE  a.date IN (CURRENT_DATE, CURRENT_DATE -1)  -- logically redundant
GROUP  BY s.grade_level
ORDER  BY today_attendance - yesterday_attendance
    -- short for: yesterday_attendance - today_attendance DESC
LIMIT  1;

WHERE a.date IN (CURRENT_DATE, CURRENT_DATE -1) is logically redundant, but makes the query much faster.

Read up and try to understand why these work, if you are not solving them yourself.