How to retrieve possible shell script exit codes when Executed shell script by Java DefaultExecutor & CommandLine?

I am executing shell script using DefaultExecutor & CommandLine from Java Program.

For successful execution receiving 0 exit value

but in case of failure or any other exit code (like 127,128,255 etc.) from shell script, not receiving respective exit code instead getting IOException.

int iExitValue = 1;
CommandLine cmd = CommandLine.parse("sh /Users/DpakG/scripts/do_Database_Operations.sh");
DefaultExecutor oDefaultExecutor = new DefaultExecutor();
oDefaultExecutor.setExitValue(0);
try {
    iExitValue = oDefaultExecutor.execute(cmd);
    log.info("Script Exit Code: " + iExitValue);
} catch (IOException e) {
    log.error("IOException occurred: ", e);
}

Any Idea How to handle exit code to perform specific custom action?

After exploring more, I am able to figure out right answer.

For Success exit codes, use setExitValues() with int array of success codes instead of 'setExitValue()' with single exit code as integer value.

int[] codes = {0,127,128};
oDefaultExecutor.setExitValues(codes);

Rest of the Failure exit codes would be captured within ExecuteException block

catch (ExecuteException exe) {
    iExitValue = exe.getExitValue();
    log.info("Script failed with exit code: " + iExitValue);
}

Complete code snippet with solution

int iExitValue = 1;
CommandLine cmd = CommandLine.parse("sh /Users/DpakG/scripts/do_Database_Operations.sh");
DefaultExecutor oDefaultExecutor = new DefaultExecutor();
int[] successCodes = {0,127,128};
oDefaultExecutor.setExitValues(successCodes);
try {
    iExitValue = oDefaultExecutor.execute(cmd);
    log.info("Script succeeded with exit code " + iExitValue); // Either 0, 127 or 128 
} catch (ExecuteException exe) {
    iExitValue = exe.getExitValue();
    log.info("Script failed with exit code: " + iExitValue);
} catch (IOException ie) {
    log.error("IOException occurred: ", ie);
}