How to do if I have an array with 1,2,3,4,5 and I want to take IF there is 4 it will return 4. If there is no 4 it will return nothing
example I have an array from 1 to 5 $numbers = '1,2,3,4,5';
I want to take 3 I want to take 3 as 3 to match the parameter 3 and not the array id
$numbers = '1,2,3,4,5';
$array = explode(',', $numbers);
echo $array[3]; // return 3
Array
(
[0] => 1
[1] => 2
[2] => 3 // get this
[3] => 4 // not this
[4] => 5
)
If the array has a value of 1,2,4,5 and I'm still looking for 3 to say nothing
$numbers = '1,2,4,5';
$array = explode(',', $numbers);
echo $array[3]; // null
Array
(
[0] => 1
[1] => 2
[2] => 4
[3] => 5
)
Or simply looking for an abbreviation of this code
<?php
$arrays = explode(',', $aa['cat']);
$setCat1 = false;
$setCat2 = false;
foreach ($arrays as $array)
{
if($array == 1){
$setCat1 = true;
}
if($array == 2){
$setCat2 = true;
}
}
I'm not sure what problem you're trying to solve, but I think this will do what you're asking for. Use in_array() to see if a value is contained in an array.
<?php
$numbers = '1,2,3,4,5';
$array = explode(',', $numbers);
$wanted_value = 3;
$output = in_array($wanted_value, $array) ? $wanted_value : NULL;
echo $output;