I wrote sympy functions with parameters. For example,
ampl, freq, phase, cte, t =sp.symbols('ampl freq phase cte t')
func=sp.Function("Func")(t)
func=ampl*sp.cos(freq*t+phase)+cte
To plot, this function, I use lambdify in this way :
funclamb=sp.lambdify([(ampl, freq, phase, cte) ,t],func)
xline=np.linspace(0,10,11)
yValues=funclamb((5, 4, 1.5, 12) ,xline)
plt.plot(xline,yValues)
But, I must be careful about the element order in the tuple : (ampl, freq, phase, cte). I wonder if there is a mean to use these parameters in a dictionary :
myParamDict={ampl: 5, freq: 4, phase: 1.5, cte: 12}
I tried different things but it does not work.
# Help on function _lambdifygenerated:
_lambdifygenerated(_Dummy_23, t)
# Created with lambdify. Signature:
func(arg_0, t)
# Expression:
ampl*cos(freq*t + phase) + cte
# Source code:
def _lambdifygenerated(_Dummy_23, t):
[ampl, freq, phase, cte] = _Dummy_23
return ampl*cos(freq*t + phase) + cte
You have to provide 2 arguments, one of which will 'unpack' to the 4 variables.
With function like:
In [5]: def foo(a,b,c):
...: print(a,b,c)
...: return None
...:
inputs can be by position, but they can also be by name or unpacked dict.
In [6]: foo(1,2,3)
1 2 3
In [7]: foo(b=3,c=1,a=1)
1 3 1
In [8]: d={'b':1,'c':2,'a':3}
In [9]: foo(**d)
3 1 2
That means your function can be called with:
In [10]: funclamb(t=np.array([1,2,3]),_Dummy_23=[1,2,3,4])
Out[10]: array([4.28366219, 4.75390225, 3.08886974])
As defined by the lambdify expression, the (ampl, freq, phase, cte) variables have to be provided as a list/tuple.