Read excel file and extract the details into a new .txt file using openpyxl

I am new to openpyxl, just started yesterday. I need to extract the data from the excel file from my local storage that excel file have 500+ rows and 50+ columns. I want to extract some specific cells or columns or rows into the .txt and .csv file.

I cannot find where is the mistake what to add in this code

from openpyxl import *
import os    

path = 'F:\\mis'
files = [i for i in os.listdir(path) if i.endswith('.xlsx')]

for f in files:
     wb = load_workbook(os.path.join(path, f))
     for row in wb['newxl.xlsx'].rows:
         with open(row[2].value+'.txt', 'w') as outfile:
              outfile.write(row[0].value)```

UPDATED ANSWER

import openpyxl
import csv
      
roster = openpyxl.load_workbook('roster.xlsx')
sheet = roster.active
col = csv.writer(open("new_roster.csv",'w',newline=""))

st_id = int(input("Enter student ID: "))
for row in sheet.rows:
    if row[0].value == st_id:
        col.writerow([cell.value for cell in row])
print("File created!")

UPDATE 2

This is how you can get the values from a specific column:

import openpyxl
roster = openpyxl.load_workbook('roster.xlsx')  
sheet = roster.active
col = sheet['B']  

for x in range(len(col)): 
    print(col[x].value) 

UPDATE 3

Return specific values from column:

import openpyxl

roster = openpyxl.load_workbook('roster.xlsx')  
sheet = roster.active

col = sheet['B']  # <-- change the column according to your file
val = input("Enter value: ")
for c in range(len(col)): 
    if val == col[c].value:
        print(f'Found {col[c].value}!')