I am trying to get file with path only without any ui.
Now i am using
[file, path] = uigetfile('*.*');
What i want to do is simple get that file without ui. something like
[file] = getfile(path)
Is there any way how to get that file but same format too as from uigetfile.
Either you know where your file is and/or use dir
and its out.folder
argument, which contains the full path, or, when your file is in your Present Working Directory, use pwd
my_folder = '/path/to/folder/';
files = dir(my_folder) % Grab all files
fullpath = [files(ii).folder files(ii).name]; % Generate full path
% Or, if the file is in the PWD
files = dir(my_folder) % Grab all files
fullpath = [pwd files(ii).name]; % Generate full path