I have seen solutions (including in this site) to the problem of having to implement a clone method in a class, so it returns a heap-allocated clone of itself even if we only have the Baseclass.
The problem come up when you have to implement in a lot of classes the same method again and again, and I remember a way of doing this when you only have to inherit from a template class (name it Cloneable) so it implements it, but the way i'm trying to do it doesn't work:
template<typename T, typename B> class Cloneable{
public:
B* clone(){return new T(*this);}
};
class Bottom {
public:
virtual void sayhi() = 0;
virtual Bottom* clone() = 0;
};
class Middle: public Cloneable<Middle, Bottom>, public Bottom {
public:
void sayhi() override {cout << "Hi from the Middle" << endl;}
};
//class Top: public Middle ...?
int main() {
Bottom* b1 = new Middle();
b1->sayhi();
delete b1;
}
I remember that the person that showed this to me actually did it with just one argument in Cloneable, but anyways, i would thank any way that you can imagine of doing this.
You could use the Curious Recurring Template Pattern where a derived class actually derives from an instanciation of it base class depending on itself. Demo:
#include <iostream>
template<typename T>
class Clonable {
public:
T* clone() {
return new T { * static_cast<T *>(this)};
}
};
template<class T>
class Base : public Clonable<T> {
public:
int x = 2;
virtual ~Base() {}
};
class Derived : public Base<Derived> {
public:
int y = 3;
};
int main() {
Base<Derived> *d = new Derived;
static_cast<Derived *>(d)->y = 6;
Derived *c = d.clone(); // we are even cloning from a Base *!
std::cout << c->x << ' ' << c->y << '\n';
delete c;
delete d;
}
It compiles with no warning and correctly outputs 2 6, proving that no slicing occurred.