How to parse a specific part of string that starts with a specific str to the first space in Oracle

I have dataset like this:

SELECT 
    1 as text_id,
    'The first is A.ACCOUNT_ID and the second one is B.IDENTITY_NO and third one is plate_number .' as full_text
FROM DUAL
UNION
SELECT 
    2,
    'The first is ARC.PREV_RECORD and the second one is ARC.NEXT_RECORD .'
FROM DUAL

I should parse all the phrases starts with " is " ; ends with first space character for each row.

So the result that I want to achieve from full_text is:

It could be less or more than 3 phrases so the row count of result could be change.

I tried to reverse text first and find the part between " si " and space but couldn't succeed

reverse(regexp_substr(reverse(full_text), ' si ([^_]*) ',1, 1))

With a lateral join on the unfolding of the dotted words via a connect by.

WITH DATA AS (
SELECT 1 as textid, 'The first is A.ACCOUNT_ID and the second one is B.IDENTITY_NO and third one is plate_number .' as full_text FROM DUAL
UNION ALL SELECT 2, 'The first is ARC.PREV_RECORD and the second one is ARC.NEXT_RECORD .' FROM DUAL
) 
SELECT t.textid, w.word
FROM DATA t
CROSS JOIN LATERAL (
  SELECT level AS lvl, REGEXP_SUBSTR(full_text, ' is ([A-Z._]+)',1, LEVEL, 'i', 1) AS word 
  FROM DUAL
  CONNECT BY LEVEL <= REGEXP_COUNT(full_text, ' is ([A-Z._]+)', 1, 'i')
) w
ORDER BY t.textid;

TEXTID | WORD           
-----: | :--------------
     1 | A.ACCOUNT_ID   
     1 | B.IDENTITY_NO  
     1 | plate_number   
     2 | ARC.PREV_RECORD
     2 | ARC.NEXT_RECORD

db<>fiddle here