Generic function typedef in C - how to get rid of initialization warning?

I'm experimenting with generic-like code and I have a function like this (a lot of not relevant code removed):

typedef uint8_t (*struct_converter_t)(void *, char *);

void convert_struct(
        struct_converter_t converter, // this is a function
        const char * file_name
){
    some_struct_t * some_struct;
    converter(some_struct, some_string_buffer);
}

And when I try to assign a function that takes some_struct_t (not void *):

static uint8_t some_converter(some_struct_t * vd, char * s);

to my struct_converter_t like this:

struct_converter_t converter = some_converter;    // WARNING HERE

I'm getting this:

initialization of 'struct_converter_t' {aka 'unsigned char (*)(void *, char *)'} from incompatible pointer type 'uint8_t (*)(some_struct_t *, char *)' {aka 'unsigned char (*)(struct <anonymous> *, char *)'} [-Wincompatible-pointer-types]

I'm not experienced in C and I would like to know if there is a way to get rid of this warning elegantly.

Solution

The function that you're assigning to the function pointer type has parameters that are incompatible with the function pointer.

Your function takes a some_struct_t * as the first parameter but the function pointer type takes a void * as the first parameter. While any object pointer can be converted to/from a void *, that does not extend to function pointer parameters.

You need to change your function to take a void * for its first parameter to be compatible with the function pointer. Then inside the function you can convert that void * parameter to a some_struct_t *.