Let l be a list of two dataframes and n a list of character strings, wherein l and n both have two elements. Also, let the number of rows of each dataframe in l be equal to the length of the vector of character strings in n.
l <- list(data.frame(x = c(1,2,3), y = c(1,2,3)),
data.frame(x = c(1,2,3,4), y = c(1,2,3,4)))
n <- list(c('a', 'b', 'c'), c('a', 'b', 'c', 'd'))
Suppose we want to replace the rownames of the two dataframes in l with the character strings in n. The desired result would be:
> l
[[1]]
x y
a 1 1
b 2 2
c 3 3
[[2]]
x y
a 1 1
b 2 2
c 3 3
d 4 4
I believe one could exploit mapply for this task, but I cannot figure how to do this.
You can use rownames<- and Map as follows
Map(`rownames<-`, l, n)
# or mapply(`rownames<-`, x = l, value = n, SIMPLIFY = FALSE)
Result
#[[1]]
# x y
#a 1 1
#b 2 2
#c 3 3
#
#[[2]]
# x y
#a 1 1
#b 2 2
#c 3 3
#d 4 4
rownames<- sets the rownames of x to value. In your case x is a single dataframe in l, and value is a vector from n. This function is applied "to the first elements of each ... argument, the second elements, the third elements, and so on.", from ?mapply.
And "Map is a simple wrapper to mapply which does not attempt to simplify the result", see ?Map