[SOLVED] How to avoid 429 error requests.get() in python?

How to avoid 429 error requests.get() in python?

I'm trying to get some data from pubg API using requests.get().

While code was executing, response.status_code returned 429.

After I got 429, I couldn't get 200.

how to fix this situation?

Here is part of my code.

for num in range(len(platform)):
   url = "https://api.pubg.com/shards/"+platform[num]+"/players/"+playerID[num]+"/seasons/"+seasonID+"/ranked"
   req = requests.get(url, headers=header)
   print(req.status_code)

[output]
200
429

Solution

As per https://developer.mozilla.org/en-US/docs/Web/HTTP/Status/429

you are sending too many requests at once/in short span of time. I recommend using time.sleep(10)

import time


for num in range(len(platform)):
   ....
   ....
   time.sleep(10)

To check the amount of time required between requests, check the Header under Network in Dev Tools - You should see a retry-after: XXX header.

If you get http status code 429, check the header under Network - You should see a retry-after: XXX header, which basically tells you for how long you should sleep between requests.