I found an example from http://pdl.perl.org/?page=FirstSteps that is:
pdl> use PDL::Graphics::Simple
pdl> imag (sin(rvals(200,200)+1)
I tried to run this example but unsuccessfully. As a consequence to that I tried to adjust the example that it would work with Gnuplot on Windows:
pdl> use PDL::Graphics::Gnuplot;
pdl> gplot(with => 'image', sin(rvals(200,200)+1) );
However, the resulting plot differs from the one that is given in PDL Book as it contains additional "V" form blue stripes:
For comparison image from PDL Book looks much cleaner:
I do not know what caused the difference.
I have just tried this with Gnuplot 5.2, bleeding-edge PDL, latest PDL::Graphics::Gnuplot (PGG) and PDL::Graphics::Simple (PGS). I get the same results as you for PGG, and for the book with PGS.
The way to make the colour-scheme be the same in both is to change the Gnuplot invocation to supply plot-options first:
pdl> use PDL::Graphics::Gnuplot
pdl> gplot({clut => 'sepia', colorbox => '', justify =>1}, with => 'image', sin(rvals(200,200)+1))
since, for better or for worse, PGS defaults to a sepia-tone. The colorbox
option is the colour-scale, and if it's not there and you want the data to still be square, you have to add a true justify
value.