Imagine, i have a column made by a bunch of of lists.
Column A
List A of userids
List B of userids
List C of userids
List D of userids
And i want to acess list A, through index. Normally, i would just do
df['Column A'][0]
End result should be:
['ELEMENT OF LIST A', 'ELEMENT OF LIST A']
But i get a weird keyerror : 0. Any ideas on what i could do so i get that specific end result? I want to know that because i need to acess a list value according to the index of my loop.
As asked here is the dict output of a single row. It was the best i could do considering the size of the suceding ones.
{'Steps': {0: '1-Onboarding + Retorno'},
'CampaignSource': {0: 'abd-ecomm-sms'},
'UserId': {0: [
'07cf01d5-5179-4fa2-b3a1-a341cfa11625@tunnel.msging.net',
'11f214d8-45dc-46d6-a9ae-8ae08a42cd7c@tunnel.msging.net',
'2d24e127-a956-4946-af1f-47341761074b@tunnel.msging.net']}}
Assuming you have an index that doesn't contain 0, like say:
df = pd.DataFrame(
{'Column A': [['a', 'b', 'c'], ['d', 'e']]},
index=['i', 'j'])
# Column A
# i [a, b, c]
# j [d, e]
Doing df['Column A'][0] would try to access the index 0 of the Series, which doesn't exist and raises a KeyError.
If you want to get all first items of the lists (as a Series) use:
df['Column A'].str[0]
output:
i a
j d
Name: Column A, dtype: object
To get the first element of the list at indices i/Column A:
df.loc['i', 'Column A'][0]
# 'a'
and for the first element of the first list of Column A:
df['Column A'].iloc[0][0]
# 'a'