previously I opened an issue asking how to take the first row in a set of records which were resolved brilliantly. Pitifully my customer changed his request a little after so this time I'm asking your help to find the middle row in a set of records i.e. having this:
TemperatureID | CastingID | TemperatureDateTime | TemperatureValue |
---|---|---|---|
1421294 | 1073513 | 2021-01-07 11:53:00.000 | 1648 |
1421295 | 1073513 | 2021-01-07 11:54:00.000 | 1698 |
1421296 | 1073513 | 2021-01-07 11:57:00.000 | 1699 |
I have to take the 1421295 record, whereas having an even number either the middle + 1 or middle - 1
So starting from this query, which return the 1421294 record to be clear
SELECT *
FROM (
SELECT
CastingID, TemperatureValue, TemperatureDateTime
, ROW_NUMBER() OVER (PARTITION BY CastingID ORDER BY CastingID) RN
FROM Production.Temperatures
where YEAR(TemperatureDateTime) = 2021 and PhaseID = 250
) A
WHERE RN = 1 and year(A.TemperatureDateTime) = 2021
can I obtain the result I want or I have to change my approach?
Edit: Updated to use a cte. Edit2: Updated to use a join rather than a sub-select to handle multiple castingIds
Since ROW_NUMBER()
is going to give us a continuous set of values, why not find MAX(RN)
, divide by 2 and then round? If the MAX(RN)
is odd, you'll get the true median, if it's even you'll get rounded down. There's likely a cleaner way to do this but something like this:
WITH cte AS (
SELECT
temperatureID
,castingID
,temperatureValue
,ROW_NUMBER() OVER (PARTITION BY castingID ORDER BY TemperatureDateTime) AS RN
FROM Temperatures
)
SELECT
*
FROM cte AS c
INNER JOIN (
SELECT
castingID
,CEILING(CONVERT(DECIMAL(7,2),MAX(RN)) / 2) AS med
FROM cte
GROUP BY castingID
) AS m ON c.rn = m.med AND c.castingID = m.castingID
Here is a SQL Fiddle with the result of the query: https://dbfiddle.uk/?rdbms=sqlserver_2019&fiddle=5b3aebf3ab4ced946c90a435d9edce3c
There's three use cases (all with different castingID
).
1.) Odd number of rows
2.) Even number of rows
3.) A single row