I have a graph that i want to compress by creating a new graph. So the vertexes are "Topological Nodes" and the edges are different objects but they have the same parent class. Now in the example i want to delete all edges with type b.
The vertices "Topological Nodes" have a Number (1,2,3). Nothing more so very simple. The edges have a reference to these nodes.
Example:
Graph {
//uncompressed Graph
1 -- 2 [label="a1"];
2 -- 3 [label="b1"];
3 -- 4 [label="b2"];
4 -- 5 [label="b3"];
5 -- 1 [label="a2"];
}
Graph {
//compressed Graph
5 -- 1 [label="a2"];
5 -- 1 [label="a1"];
}
What i have so far is this:
public void compression(Graph<TopologicalNode, IdentifiedObject> unCompressedGraph){
Set<SubGeographicalRegion> networks = datamodel.equipmentProfile.keySet();
for (SubGeographicalRegion subGeographicalRegion : networks) {
Graph<TopologicalNode, IdentifiedObject> compressedGraph = GraphTypeBuilder
.<TopologicalNode, IdentifiedObject>undirected().allowingSelfLoops(true)
.edgeClass(IdentifiedObject.class).buildGraph();
ArrayList<PowerTransformer> powerTransformers = getPTsFromSubnet(subGeographicalRegion);
for(PowerTransformer powerTransformer :powerTransformers) {
for (PowerTransformerEnd powerTransformerEnd : powerTransformer.getEnds()) {
if (unCompressedGraph.vertexSet().stream().filter(r -> r.equals(powerTransformerEnd.getTerminal().getTopologicalNode())).findAny().isPresent()) {
TopologicalNode start = unCompressedGraph.vertexSet().stream().filter(r -> r.equals(powerTransformerEnd.getTerminal().getTopologicalNode())).findAny().get();
compressedGraph.addVertex(start);
ArrayList<TopologicalNode> nodesToBeCompressed = new ArrayList<>();
Iterator<TopologicalNode> iterator = new DepthFirstIterator<>(unCompressedGraph, start);
while (iterator.hasNext()) {
TopologicalNode nextNode = iterator.next();
Set<IdentifiedObject> eqs = unCompressedGraph.edgesOf(nextNode);
//TODO: How to go on?
}
}
}
}
}
}
So i dont really know how to go on and i am new to JGraphT.
It seems you intend to delete an edge by removing it and merging the nodes touched by the edges. You could do this by:
2a. If there are multiple edges between u an v, then just remove the edge and there's nothing else to do.
2b. If there's only one edge between u and v, we proceed as follows. Create a new vertex w. Vertex w will be the new 'merged' node. Remove edge e1. Connect all edges from u to its neighbors to w. Do the same for v. Remove nodes u and v.
In code, this translates to:
public static void main(String[] args){
//Create a graph
Graph<Integer, String> g =
new Pseudograph<>(SupplierUtil.createIntegerSupplier(1), null, false);
for(int i=0; i<5; i++)
g.addVertex();
g.addEdge(1,2,"a1");
g.addEdge(2,3,"b1");
g.addEdge(3,4,"b2");
g.addEdge(4,5,"b3");
g.addEdge(5,1,"a2");
removeEdge(g,"b1");
removeEdge(g,"b2");
removeEdge(g,"b3");
System.out.println(g);
}
private static void removeEdge(Graph<Integer, String> g, String edge){
if(!g.containsEdge(edge))
throw new RuntimeException(String.format("Cannot delete edge %s because this edge does not exist in the graph!", edge));
Integer u=g.getEdgeSource(edge);
Integer v=g.getEdgeTarget(edge);
//Case 2a: there are multiple edges between vertex u and v
if(g.getAllEdges(u,v).size()>1){
g.removeEdge(edge);
return;
}
//Case 2b: there is only 1 edge between u and v. Delete the edge, and merge nodes u and v into new node w.
g.removeEdge(edge);
Integer w=g.addVertex();
Set<String> edgesOfU = new HashSet<>(g.edgesOf(u));
Set<String> edgesOfV = new HashSet<>(g.edgesOf(v));
//Remove all edges between u and its neighbors and re-add those edges for node w
for(String e : edgesOfU){
Integer neighbor = Graphs.getOppositeVertex(g,e,u);
g.removeEdge(e);
g.addEdge(w,neighbor,e);
}
//Remove all edges between v and its neighbors and re-add those edges for node w
for(String e : edgesOfV){
Integer neighbor = Graphs.getOppositeVertex(g,e,v);
g.removeEdge(e);
g.addEdge(w,neighbor,e);
}
//Nodes u and v have been replaced by w, so we can safely remove u and v
g.removeVertex(u);
g.removeVertex(v);
}
When executing this code we get the desired graph:
([1, 8], [a1={8,1}, a2={8,1}])
Note that, the delete-and-merge operation could produce graphs with multiple edges between the same node, or self-loops, so we need to use a Pseudograph as underlying graph type.