The code below works and sets the color of the four lines with the three values for rgb. The three rgb values are filled in an array (Clr) which is not very clear. Is there an alternative way for instant by using Hex numbers, ColorIndex or the predefined colors like vbBlack?
Sub CreateChart()
Dim i As Long
Dim j As Long
Dim Clr() As Variant
'Clr = Array("vbBlack", "vbBlue", "vbRed", "vbCyan", "vbGreen", "vbMagenta") ' colors as types
'Clr = Array("&H0", "&HFF0000", "&Hff", "&HFFFF00", "&HFF00", "&HFF00FF") ' Hex of colors as String
'Clr = Array(&H0, &HFF0000, &HFF, &HFFFF00, &HFF00, &HFF00FF) ' Hex Values of colors
'Clr = Array(&H0, &HFF0000, &HFF, &HFFFF00, &HFF00, &HFF00FF) ' IndexColor
Clr = Array(0, 0, 0, 0, 0, 255, 255, 0, 0, 0, 255, 255, 0, 255, 0, 255, 0, 255)
With Charts.Add
.ChartType = xlXYScatterLinesNoMarkers
.SetSourceData Source:=Sheets("Plot").Range("A12:E213")
j = 0
For i = 2 To 5
With .FullSeriesCollection(i - 1).Format.Line
.ForeColor.RGB = RGB(Clr(j), Clr(j + 1), Clr(j + 2))
j = j + 3
End With
Next
End With
End Sub
Actually, your code works well, just get rid of quotation marks and RGB
function. Also there's nothing wrong with hex values, they work fine.
Sub CreateChart()
Dim Color As Variant
Dim Source as Range
Dim i As Long
Set Source = Sheets("Plot").Range("A12:E213")
Color = Array(vbBlack, vbBlue, vbRed, vbCyan, vbGreen, vbMagenta)
' Array(&H0, &HFF0000, &HFF, &HFFFF00, &HFF00, &HFF00FF) works as well
With Charts.Add
.ChartType = xlXYScatterLinesNoMarkers
.SetSourceData Source
For i = 1 To .FullSeriesCollection.Count
.FullSeriesCollection(i).Format.Line.ForeColor.RGB = Color(i - 1)
Next i
End With
End Sub
To use Color(i)
instead of somewhat clumsy Color(i - 1)
we should add Option Base 1
to start Array
index from one by default. But it's up to you, of course.
P.S. Take a look at xlRGBColor enumeration