I am using VideoThumbanil class to fetch an Uint8List image of a video like this:
final uint8List = await VideoThumbnail.thumbnailData(video: videoFile.path,);
After doing so, i am converting the Uint8LIST to an Image using the following code:
Image image = Image.memory(uint8List);
What I want to do is to convert this image to a File class instance so that I can upload this image to my server. Code for uploading on server is:
void asyncFileUpload(File file) async {
//create multipart request for POST or PATCH method
var request = http.MultipartRequest("POST", Uri.parse("127.0.0.1/upload"));
//create multipart using filepath, string or bytes
var pic = await http.MultipartFile.fromPath("image", file.path);
//add multipart to request
request.files.add(pic);
var response = await request.send();
//Get the response from the server
var responseData = await response.stream.toBytes();
var responseString = String.fromCharCodes(responseData);
print(responseString);
}
You can fetch the path to the temporary directory:
final tempDir = await getTemporaryDirectory();
After doing so, you can create a File in that temporary directory:
File fileToBeUploaded = await File('${tempDir.path}/image.png').create();
This way your file has a path and it's instance has been created. Now, you can write the file as:
fileToBeUploaded.writeAsBytesSync(uint8List);
Now, you can use fileToBeUploaded as File that is actually an image.
Complete code:
final uint8List = await VideoThumbnail.thumbnailData(video: videoFile.path,);
final tempDir = await getTemporaryDirectory();
File fileToBeUploaded = await File('${tempDir.path}/image.png').create();
fileToBeUploaded.writeAsBytesSync(uint8List);
asyncFileUpload(fileToBeUploaded);