class Example:
def __init__(self, x):
self.x = x
def function(self, y=self.x):
pass
Example(72)
When I run this code, I get the following error.
Traceback (most recent call last):
File "/home/millertime/Desktop/example.py", line 1, in <module>
class Example:
File "/home/millertime/Desktop/example.py", line 7, in Example
def function(self, y=self.x):
NameError: name 'self' is not defined
Evidently, Python isn't happy with having an argument preset to a class variable. Is there a proper way to do this? I know the class info is being passed in the first argument, self. Any way to reference this further along to make my code possible? I've tried changing y=self.x to y=x, but as I suspected this just threw a NameError. I'm well aware of other ways to do this inside the function, but I'm interested if it's possible or not.
In python, the expressions in default arguments of functions are calculated when the function is defined, not when it's called. In the case above there won't be any instantiation hence the error.
You can do this instead
class Example:
def __init__(self, x):
self.x = x
def function(self, y=None):
if y is None:
y=self.x
pass
Example(72)