Here, I've three radio group in a single page. But in the entire page I want to select only one radio option. Like if I'm selecting Monday then Tuesday selection should be unchecked automatically. How can I proceed with the logic, below logic is not working as expected.
sample JSON :
{
report:[
{
day:'Monday',
slot:[
'9-10am',
'10-11am',
'11-12am'
]
},{
day:'Tuesday',
slot:[
'9-10am',
'10-11am',
'11-12am'
]
},{
day:'Wednesday',
slot:[
'9-10am',
'10-11am',
'11-12am'
]
}
]}
JS code
for(var I=0; I<reports.length; I++){
var radios = document.getElementsByTagName('input')
if(radios[I].type === 'radio' && radios[I].checked){
document.getElementById(radios[I].id).checked = false
}
If you're able to create radio buttons in SurveyJS, you should be able to give the button group a name, so there would be no need for any additional JavaScript. Check out their documentation for an example.
Looks like the sort of nested structure you have for the buttons could be achieved with something like a dynamic panel or cascading conditions in SurveyJS. You should be able to render the available time slots dynamically with "visibleIf"
based on the selected day.
I would definitely dig around the documentation of SurveyJS to find a solution there rather than hacking your way around it. But solely as an exercise, the problem in your current code could be that you're selecting a button by ID, which will not work correctly if you have tried to give the same ID to multiple buttons. After all, you already have the target button as radios[I]
, so you could just use radios[I].checked = false
. Or the issue could be that you're unchecking the selected button AFTER the new selection has been made, which might actually uncheck the button you just clicked. Hard to say without additional information, but in any case, looping your inputs based on a value that might be something else than the actual number of inputs (you're using reports.length
) is probably not the best idea, since that value might be different from the number of inputs in your form, which would mean that not all of them are included in the loop. Here are a couple of examples of what you could do instead:
// Get all radio buttons
const radioButtons = document.querySelectorAll('input[type="radio"]')
// If you need to uncheck the previously selected one (don't do this if you can avoid it!)
radioButtons.forEach(radioButton => {
// Use a mousedown event instead of click
// This gives you time to uncheck the previous one before the new one gets checked
radioButton.addEventListener('mousedown', () => {
// Get the currently selected button and uncheck it
const currentlySelected = document.querySelector('input[type="radio"]:checked')
if (currentlySelected) currentlySelected.checked = false
})
})
// You can add further options to the querySelector, such as [name]
// This gets the currently selected button in the specified group
const checkedRadioButton = document.querySelector('input[type="radio"][name="group-name"]:checked')
Here's a fiddle demonstrating this sort of "fake" radio button functionality (without a "name" attribute).