I'm trying to convert a string to an integer (which is actually a binary number) so that I can output the DEC value, but where the answer SHOULD be 63 (00111111), it's giving me -19961 as an output? It would be great if someone can help me correctly convert the string to an int :)
// C++ code
//
const int button = 13;
int buttonPressed = 0;
int counter = 0;
int myInts[] = {0, 0, 1, 1, 1, 1, 1, 1};
void setup()
{
Serial.begin(9600);
pinMode(button, INPUT);
}
void loop()
{
buttonPressed = digitalRead(button);
if (buttonPressed == HIGH){
counter = count();
//rial.println(counter);
}
else{
Serial.println("Button not pressed");
}
delay(1000);
}
int count()
{
String myString = ""; //Empty string for constructing
int add = 0;
int i = 0;
//Should add all the values from myInts[] into a string
while(i < 8){
myString = String(myString + myInts[i]);
Serial.println(add);
delay(1000);
add++;
i++;
}
Serial.println(myString);
int myNumber = myString.toInt(); //Convert the string to int
Serial.println(myNumber, DEC); //Should print 63 in this case
return add;
}
Your code currently does the following:
int
is -32768 to 32767 (65536 possible values), so the number you really have is 111111 - 2*65536 = -19961.I don't believe that there's an overload of Arduino's ToInt that converts a binary string to an integer. Depending on the C++ support in Arduino, you may be able to use std::stoi
as described here.
Instead, you may choose to do the conversion yourself - you can keep track of a number sum
, and at each loop iteration, double it and then add the next bit:
int sum = 0;
for(int i = 0; i < 8; i++) {
sum *= 2;
sum += myInts[i];
// print and delay if you want
}
Over the eight iterations, sum
ought to have values 0, 0, 1, 3, 7, 15, 31, and finally 63