I have a list that I'm trying to reformat.
data = ['Height:\n \n 6\' 4"', 'Weight:\n \n 185 lbs.', 'Reach:\n \n 80"', 'STANCE:\n \n Switch', 'DOB:\n \n \n Jul 22, 1989', 'SLpM:\n \n\n 3.93', 'Str. Acc.:\n \n 49%', 'SApM:\n \n 2.67', 'Str. Def:\n \n 59%', '', 'TD Avg.:\n \n 0.00', 'TD Acc.:\n \n 0%', 'TD Def.:\n \n 78%', 'Sub. Avg.:\n \n 0.2']
I've tried using strip.
for info in data:
info.strip('\n \n ')
But, I'm still getting the same output.
How would I be able to delete the whitespace of "\n \n " within each index of the list. To get the following?
data = ['Height: 6\' 4"', 'Weight: 185 lbs.', 'Reach: 80"', 'STANCE: Switch', 'DOB: Jul 22, 1989', 'SLpM: 3.93', 'Str. Acc.: 49%', 'SApM: 2.67', 'Str. Def: 59%', '', 'TD Avg.: 0.00', 'TD Acc.: 0%', 'TD Def.: 78%', 'Sub. Avg.: 0.2']
Here is my approach: Replace the colon and the following blank spaces with a colon and a space:
import re
pattern = re.compile(r":\s*")
new_data = [
pattern.sub(": ", datum)
for datum in data
]
new_data then become:
['Height: 6\' 4"',
'Weight: 185 lbs.',
'Reach: 80"',
'STANCE: Switch',
'DOB: Jul 22, 1989',
'SLpM: 3.93',
'Str. Acc.: 49%',
'SApM: 2.67',
'Str. Def: 59%',
'',
'TD Avg.: 0.00',
'TD Acc.: 0%',
'TD Def.: 78%',
'Sub. Avg.: 0.2']