Suppose, I declare a local variable in a CUDA kernel function for each thread:
float f = ...; // some calculations here
Suppose also, that the declared variable was placed by a compiler to a local memory (which is the same as global one except it is visible for one thread only as far as I know). My question is will the access to f be coalesced when reading it?
I don't believe there is official documentation of how local memory (or stack on Fermi) is laid out in memory, but I am pretty certain that mulitprocessor allocations are accessed in a "striped" fashion so that non-diverging threads in the same warp will get coalesced access to local memory. On Fermi, local memory is also cached using the same L1/L2 access mechanism as global memory.