How to pass a pointer to function which changes the pointer, using CFFI

I have the following c function into which I want to pass a dummy pointer so that I can retrieve the generated array:

int generateFloatArr(float **outputArr){
  float result[4] = {1.0,2.0,3.0,4.0};
  *outputArr=&result;
  return 4;
}

With it, I can do the following in c:

  float *output;

  int arrLen = generateFloatArr(&output);
  printf("%f \n",output[0]); //prints "1.000000"

With CFFI I am stuck interacting with this function.

I can create a pointer with:

p_floatArr=ffi.new("float *")

But I'm unsure how to get the address of p_floatArr to pass into lib.generateFloatArr().

I tried this instead which the python-CFFI docs seem to suggest doing:

p_p_floatArr=ffi.new("float **")
lib.generateFloatArr(p_p_floatArr)
print(p_p_floatArr[0][0])

However the float value is incorrect. If I do the analog of the above in c:

  float **output;

  generateFloatArr(output);
  printf("%f \n",output[0][0]); 

This gives a segfault.

How can I properly pass a pointer (to a pointer) to this function?

within generateFloatArr(), either:

1. *outputArr needs to be allocated with malloc() and then filled with values, or

2. result needs to be initialized as static const float result[4]={...}

From the python side, it works to do:

p_p_floatArr=ffi.new("float **")
lib.generateFloatArr(p_p_floatArr)
print(p_p_floatArr[0][0])