I need a regex pattern to remove all numeric input from the beginning of a field that stops at the first alphabetic character and leaves any remaining numbers that follow alphabetic characters.
Here is the simplest test case.
CREATE TABLE tempdemo (tdfields varchar(10));
INSERT INTO tempdemo (tdfields) VALUES ('1'), ('11'), ('111'), ('a'), ('ab'), ('abc'), ('1a'), ('a1');
SELECT REGEXP_REPLACE(tdfields, '^[0-9]*$', '') FROM tempdemo;
From the code, I would like the following output: :blank:, :blank:, :blank:, a, ab, abc, a, a1
Right now, the regex pattern leaves '1a' instead of 'a' which is undesireable.
Any help would be greatly appreciated. Thanks.
You can use
CREATE TABLE tempdemo (tdfields varchar(10));
INSERT INTO tempdemo (tdfields) VALUES ('1'), ('11'), ('111'), ('a'), ('ab'), ('abc'), ('1a'), ('a1');
SELECT REGEXP_REPLACE(tdfields, '^[0-9]+', '') FROM tempdemo;
It will remove one or more digits from the start of the string.
More details:
^
- start of string[0-9]+
- one or more digits.$
matches the start of string position.
Note that ^[0-9]*
is not a good pattern here since it matches any string, and +
variation will only match when necessary, when there are digits at the start of the string.