[SOLVED] Python: how to get each element in a str list and then put the first element into the first file in a directory, second element in the second dir?

Python: how to get each element in a str list and then put the first element into the first file in a directory, second element in the second dir?

I'm trying to deal with txt files.

I have a 2D list called reps = [], len(reps) = 41, I also have a directory called replies, which contains 34 txt files.

I want to do like this:

reps[0][0] is the first line of the file1.txt under the replies directory, reps[0][1] is the second line etc.
reps[1][0] is the first line of the second file2.txt
Until all 34 txt files have been replaced then it's done

how can I achieve this?

I would be very appreciate

Solution

reps = ...
for i, lst in enumerate(reps, start=1):
    with open(f"replies/file{i}.txt", "w") as f:
        f.writelines(line + '\n' for line in lst)

Although if you indeed have 41 lists of strings in reps, this will result in 41 files, not 34:

replies/file1.txt
replies/file2.txt
...
replies/file41.txt

If I misunderstood you and you actually really want to just replace exactly 34 files that already exist in that directory, you can always just add a conditional break in the beginning of the loop:

...
for i, lst in enumerate(reps, start=1):
    if i > 34:
        break
    ...

Note that writelines expects each element in the provided iterable to provide its own line seperator, which is why the generator produces line + '\n' for every line.